95p+5p^2=4406

Solution for 95p+5p^2=4406 equation:

95p+5p^2=4406

We move all terms to the left:

95p+5p^2-(4406)=0

a = 5; b = 95; c = -4406;
Δ = b2-4ac
Δ = 952-4·5·(-4406)
Δ = 97145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(95)-\sqrt{97145}}{2*5}=\frac{-95-\sqrt{97145}}{10}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(95)+\sqrt{97145}}{2*5}=\frac{-95+\sqrt{97145}}{10}
$